35m^2-16=0

Solution for 35m^2-16=0 equation:

35m^2-16=0

a = 35; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·35·(-16)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{35}}{2*35}=\frac{0-8\sqrt{35}}{70}
=-\frac{8\sqrt{35}}{70}
=-\frac{4\sqrt{35}}{35}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{35}}{2*35}=\frac{0+8\sqrt{35}}{70}
=\frac{8\sqrt{35}}{70}
=\frac{4\sqrt{35}}{35}
$